Answer
The name of the compound is-
$1,1-diethyl-2-methylcyclobutane$
Work Step by Step
The given compound is a cyclo alkane. It's carbon ring contains 4 carbon atoms (-but). There are two ethyl and one methyl substituents. Giving the position numbers so as to get the lowest numbers for the substituents, we see that the two ethyl substituents are at position 1 and one methyl substituent at position 2. So, name of the compound is-
$1,1-diethyl-2-methylcyclobutane$.