Answer
Least basic --> Most basic
$HSO_4^-$ < $H_2O$ < $CH_3COO^-$ < $NH_3$ < $CH_3O^-$ ~ $NaOH$ < $^-NH_2$
Work Step by Step
The conjugate bases of the weakest acids will be the strongest bases. The $pK_a$ values of the conjugate acids are listed in the brackets.
Least basic --> Most basic
$HSO_4^-$ (from -5) < $H_2O$ (from -1.7) < $CH_3COO^-$ (from 4.74) < $NH_3$ (from 9.4) < $CH_3O^-$ (from 15.5) ~ $NaOH$ (from 15.7) < $^-NH_2$ (from 33 (or 36))
