Answer
Please see the work below.
Work Step by Step
We know that the orbital diagram for $1s^2\space 2s^2\space 2s^4$ and the ground state of the oxygen is
$\uparrow \downarrow1s \uparrow \downarrow 2s\uparrow \downarrow\uparrow \downarrow 2p$
General Chemistry 10th Edition
by Ebbing, Darrell; Gammon, Steven D.
Published by
Cengage Learning
ISBN 10:
1-28505-137-8
ISBN 13:
978-1-28505-137-6
Chapter 8 - Electron Configurations and Periodicity - Questions and Problems - Page 329: 8.7
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