Answer
$6.578\times 10^{14}\frac{m}{s}$
Work Step by Step
We know that
$v=\frac{c}{\lambda}$
We plug in the known values to obtain:
$v=\frac{3.00\times 10^8}{4.56\times 10^{-7}}=6.578\times 10^{14}\frac{m}{s}$
General Chemistry 10th Edition
by Ebbing, Darrell; Gammon, Steven D.
Published by
Cengage Learning
ISBN 10:
1-28505-137-8
ISBN 13:
978-1-28505-137-6
Chapter 7 - Quantam Theory of the Atom - Exercises - Page 272: 7.2
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