Answer
Please see the work below.
Work Step by Step
We know that
$10.0g\space N_2H_4\times\frac{1mol\space N_2H_4}{32.02g}\times \frac{1mol\space N_2O_4}{2mol\space N_2H_4}\times \frac{-1049KJ}{1mol\space N_2O_4}=-163.8J$
General Chemistry 10th Edition
by Ebbing, Darrell; Gammon, Steven D.
Published by
Cengage Learning
ISBN 10:
1-28505-137-8
ISBN 13:
978-1-28505-137-6
Chapter 6 - Thermochemistry - Exercises - Page 241: 6.7
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