General Chemistry 10th Edition

Published by Cengage Learning
ISBN 10: 1-28505-137-8
ISBN 13: 978-1-28505-137-6

Chapter 5 - The Gaseous State - Questions and Problems - Page 221: 5.91

Answer

Please see the work below.

Work Step by Step

We know that $u_{330k}=(\frac{3RT}{M})^{\frac{1}{2}}$ We plug in the known values to obtain: $U_{330k}=(\frac{3\times 8.31\times (57+273)}{352\times 10^{-3}})^{\frac{1}{2}}=1.528\times 10^2\frac{m}{s}$
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