General Chemistry 10th Edition

Published by Cengage Learning
ISBN 10: 1-28505-137-8
ISBN 13: 978-1-28505-137-6

Chapter 5 - The Gaseous State - Questions and Problems - Page 220: 5.61

Answer

$143C^{\circ}$

Work Step by Step

We know that $PV=nRT$ This can be rearranged as $T=\frac{PV}{nR}$ We plug in the known values to obtain: $T=\frac{3.50\times 4.00}{0.410\times 0.08206}=416K$ $T=416-273=143C^{\circ}$
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