General Chemistry 10th Edition

Published by Cengage Learning
ISBN 10: 1-28505-137-8
ISBN 13: 978-1-28505-137-6

Chapter 3 - Calculations with Chemical Formulas and Equations - Exercises - Page 94: 3.5

Answer

0.452 mol $HNO_{3}$.

Work Step by Step

Strategy: We have to convert mass to moles. So the conversion factor is 1 mol/Molar mass. Moles in 28.5 g $HNO_{3}$ Molar mass $HNO_{3}$ =1 x 1.007 + 1 x 14.006 + 3 x 15.999 Molar mass $HNO_{3}$ = 63.01 g/mol therefore: 28.5 g x $\frac{1 mol(HNO_{3})}{63.01 g($HNO_{3})}$ = 0.452 mol $HNO_{3}$ So 28.5 g $HNO_{3}$ is 0.452 mol $HNO_{3}$.
Update this answer!

You can help us out by revising, improving and updating this answer.

Update this answer

After you claim an answer you’ll have 24 hours to send in a draft. An editor will review the submission and either publish your submission or provide feedback.