Answer
Please see the work below.
Work Step by Step
We can find the amount of heat as
$3.5\times 10^7g\space H_2\times\frac{1 mol\space H_2}{2.016g\space H_2}\times \frac{-448KJ}{2mol\space H_2}=-4.201\times 10^9KJ$
General Chemistry 10th Edition
by Ebbing, Darrell; Gammon, Steven D.
Published by
Cengage Learning
ISBN 10:
1-28505-137-8
ISBN 13:
978-1-28505-137-6
Chapter 21 - Chemistry of the Main-Group Elements - Questions and Problems - Page 931: 21.117
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