Answer
Please see the work below.
Work Step by Step
The chemical equation is
$C_6H_5NH_2+H_2O\rightarrow \leftarrow C_6H_5NH_3^+ +OH^-$
The expression fro $K_b$ is
$K_b=\frac{[C_6H_5NH_3]^+][OH^-]}{[C_6H_5NH_2]}$
General Chemistry 10th Edition
by Ebbing, Darrell; Gammon, Steven D.
Published by
Cengage Learning
ISBN 10:
1-28505-137-8
ISBN 13:
978-1-28505-137-6
Chapter 16 - Acid-Base Equilibria - Questions and Problems - Page 703: 16.50
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