Answer
Please see the work below.
Work Step by Step
We know that
$PH=-log[H_3O]^{+}$
$PH=-log(1.5\times 10^{-3})$
$PH=2.823$
General Chemistry 10th Edition
by Ebbing, Darrell; Gammon, Steven D.
Published by
Cengage Learning
ISBN 10:
1-28505-137-8
ISBN 13:
978-1-28505-137-6
Chapter 15 - Acids and Bases - Questions and Problems - Page 660: 15.95
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