Answer
Please see the work below.
Work Step by Step
We know that
$[PCl_5]=\frac{[PCl_3][Cl_2]}{k_c}$
We plug in the known values to obtain:
$[PCl_5]=\frac{0.020(0.020)}{0.0415}=9.63\times 10^{-3}M$
General Chemistry 10th Edition
by Ebbing, Darrell; Gammon, Steven D.
Published by
Cengage Learning
ISBN 10:
1-28505-137-8
ISBN 13:
978-1-28505-137-6
Chapter 14 - Chemical Equilibrium - Exercises - Page 607: 14.9
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