General Chemistry 10th Edition

Published by Cengage Learning
ISBN 10: 1-28505-137-8
ISBN 13: 978-1-28505-137-6

Chapter 14 - Chemical Equilibrium - Exercises - Page 598: 14.3

Answer

Please see the work below.

Work Step by Step

We know that $K_c=\frac{[CO_2][H_2]}{[CO][H_2O]}$ We plug in the known values to obtain: $K_c=\frac{0.043(0.043)}{0.057)(0.057)}=0.569$
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