General Chemistry 10th Edition

Published by Cengage Learning
ISBN 10: 1-28505-137-8
ISBN 13: 978-1-28505-137-6

Chapter 13 - Rates of Reaction - Questions and Problems - Page 582: 13.55

Answer

Please see the work below.

Work Step by Step

We know that $K=\frac{Rate}{[ClO_2]^2[OH^-]}$ We plug in the known values to obtain: $K=\frac{0.0248\frac{M}{s}}{[0.060M]^2[0.030M]}=\frac{2.29\times 10^{2}}{M^2s}$
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