Answer
Please see the work below.
Work Step by Step
We know that
$K=\frac{Rate}{[ClO_2]^2[OH^-]}$
We plug in the known values to obtain:
$K=\frac{0.0248\frac{M}{s}}{[0.060M]^2[0.030M]}=\frac{2.29\times 10^{2}}{M^2s}$
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