Answer
Please see the work below.
Work Step by Step
We know that
$Rate=\frac{\Delta [NH_4NO_2]}{\Delta t}$
We plug in the known values to obtain:
$Rate=\frac{[0.0432M-0.500M]}{[3.00hr-0.00hr]}=2.27\times 10^{-2}\frac{M}{hr}$
General Chemistry 10th Edition
by Ebbing, Darrell; Gammon, Steven D.
Published by
Cengage Learning
ISBN 10:
1-28505-137-8
ISBN 13:
978-1-28505-137-6
Chapter 13 - Rates of Reaction - Questions and Problems - Page 581: 13.43
Update this answer!
You can help us out by revising, improving and updating this answer.
Update this answerAfter you claim an answer you’ll have 24 hours to send in a draft. An editor will review the submission and either publish your submission or provide feedback.
