General Chemistry 10th Edition

Published by Cengage Learning
ISBN 10: 1-28505-137-8
ISBN 13: 978-1-28505-137-6

Chapter 12 - Solutions - Questions and Problems - Page 530: 12.99

Answer

Please see the work below.

Work Step by Step

We know that $M=\frac{\pi}{RT}$ We plug in the known values to obtain: $M=\frac{7.7atm}{(0.0821\frac{L.atm}{K.mol})(37+273)K}=0.302\frac{mol}{L}$
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