Answer
Please see the work below.
Work Step by Step
We know that
$\Delta T_b=K_bc_m$
We plug in the known values to obtain:
$\Delta T_b=3\times \frac{0.512C^{\circ}}{m}\times 0.050m=0.0768C^{\circ}$
General Chemistry 10th Edition
by Ebbing, Darrell; Gammon, Steven D.
Published by
Cengage Learning
ISBN 10:
1-28505-137-8
ISBN 13:
978-1-28505-137-6
Chapter 12 - Solutions - Exercises - Page 517: 12.17
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