General Chemistry 10th Edition

Published by Cengage Learning
ISBN 10: 1-28505-137-8
ISBN 13: 978-1-28505-137-6

Chapter 12 - Solutions - Exercises - Page 504: 12.10

Answer

Please see the work below.

Work Step by Step

We know that $Volume \space of \space solution=1205.4g \frac{1ml}{1.045g}=1153.49ml=1.15349L$ We also know that $molarity=\frac{moles \space of solute}{Liters \space of \space solution}$ $molarity=\frac{3.42}{1.15349}=2.9649\frac{mol}{L}$
Update this answer!

You can help us out by revising, improving and updating this answer.

Update this answer

After you claim an answer you’ll have 24 hours to send in a draft. An editor will review the submission and either publish your submission or provide feedback.

GradeSaver will pay $15 for your literature essays
GradeSaver will pay $25 for your college application essays
GradeSaver will pay $50 for your graduate school essays – Law, Business, or Medical
GradeSaver will pay $10 for your Community Note contributions
GradeSaver will pay $500 for your Textbook Answer contributions