Answer
Please see the work below.
Work Step by Step
We know that
$S_2=\frac{P_2S_1}{P_1}$
We plug in the known values to obtain:
$S_2=\frac{159mm\space Hg\times 0.0404g\frac{O_2}{L}}{760mm\space Hg}=8.45\times 10^{-3}g\frac{O_2}{L}$
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