Chemistry: The Molecular Nature of Matter and Change 7th Edition

Published by McGraw-Hill Education
ISBN 10: 007351117X
ISBN 13: 978-0-07351-117-7

Chapter 24 - Problems: 24.137

Answer

931.5 MeV

Work Step by Step

We know that one atomic mass unit is defined as 1/12th the mass of an atom of Carbon-12 isotope. As such 1 amu=1.6606×10−27 kg Velocity of light c in vacuum is =2.9979×108 ms−1 Using the Einstein's mass energy equivalence relation we get E=mc2 E=1.6606×10−27×(2.9979×108)2 J We also know that 1 eV=1 electronic charge in C×1 V=1.60218×10−19 J Therefore, we get E=1.6606×10−27×(2.9979×108)21.60218×10−19eV ⇒E=931.5 MeV , rounded to one decimal place
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