Answer
See explanation below.
Work Step by Step
Given reaction is:
Al3+ + 3 e- --> Al
Reduction of aluminum ions to aluminum metal results in transfer of three electrons.
(305 C)(1mole-/96485 C)(1mol Al/3 mole-)(26.98 g Al/ 1 mol Al) = 0.028 g Ra
Chemistry: The Molecular Nature of Matter and Change 7th Edition
by Silberberg, Martin; Amateis, Patricia
Published by
McGraw-Hill Education
ISBN 10:
007351117X
ISBN 13:
978-0-07351-117-7
Chapter 21 - Problems - Page 972: 21.104
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