Chemistry: The Molecular Nature of Matter and Change 7th Edition

Published by McGraw-Hill Education
ISBN 10: 007351117X
ISBN 13: 978-0-07351-117-7

Chapter 21 - Problems: 21.50

Answer

See explanation below.

Work Step by Step

When metal A reacts with metal B salt, solid colored product is formed on metal A. Conclusion is that Product is solid metal B and A is better reducing agent than B. When metal B reacts with acid gas bubbles are formed. Conclusion is that H2 gas produced as result of reduction of H+ and B is better reducing agent than acid. When metal A reacts with Metal C salt no reaction occurs. Conclusion is that C should be a better reducing agent than A. As C is a better reducing agent than A, a better reducing agent than B and B reduces acid, then C might also reduce acid to form H2 bubbles. Hence the order of strength of reducing agents is: C > A > B.
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