Chemistry: The Molecular Nature of Matter and Change 7th Edition

Published by McGraw-Hill Education
ISBN 10: 007351117X
ISBN 13: 978-0-07351-117-7

Chapter 18 - Problems - Page 818: 18.31

Answer

$4.8*10^{-4}$ OH- mol / L

Work Step by Step

Since the p in pH stands for negative log... $10^{-3.15}-10^{-3.65} = 4.8*10^{-4}$ Since we are making the pH go up we add OH-.
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