Chemistry: The Molecular Nature of Matter and Change 7th Edition

Published by McGraw-Hill Education
ISBN 10: 007351117X
ISBN 13: 978-0-07351-117-7

Chapter 12 - Problems: 12.146

Answer

3.82 x 10¯23 g/atom

Work Step by Step

1) Calculate the average mass of one atom of Na: 22.99 g mol¯1 ÷ 6.022 x 1023 atoms mol¯1 = 3.82 x 10¯23 g/atom 2) Determine atoms in 1 cm3: 0.968 g / 3.82 x 10¯23 g/atom = 2.54 x 1022 atoms in 1 cm3 3) Determine volume of the unit cell: (4.29 x 10¯8 cm)3 = 7.89 x 10¯23 cm3 4) Determine number of unit cells in 1 cm3: 1 cm3 / 7.89 x 10¯23 cm3 = 1.27 x 1022 unit cells 5) Determine atoms per unit cell: 2.54 x 1022 atoms / 1.27 x 1022 unit cells = 2 atoms per unit cell
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