# Chapter 2 - Atoms, Molecules, and Ions - Exercises: 2.61a

$CaBr_{2}$

#### Work Step by Step

The overall charge of the compound must be neutral. The problem gives the charge of Calcium (Ca), +2, and the charge of Bromine (Br), -1. To cancel out the +2 of the Calcium ion, there must be two Bromine ions, for Bromine ions only have a charge of -1 while Calcium ions have a charge of +2. Thus, the compound is $CaBr_{2}$.

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