Answer
569 mL
Work Step by Step
$V_{1}=486\,mL$
$T_{1}=(-8+273)K= 265\,K$
$T_{2}=(37+273)K= 310\,K$
.
As there is no change in the number of moles and pressure, we can use Charles's law to find $V_{2}$.
$\frac{V_{1}}{T_{1}}=\frac{V_{2}}{T_{2}}$
$\implies V_{2}=\frac{V_{1}T_{2}}{T_{1}}=\frac{486\,mL\times310\,K}{265\,K}=569\,mL$
