Chapter 7 - Section 7.2 - Molar Mass and Calculations - Questions and Problems - Page 221: 7.24c

2.0 moles of C.

1. Calculate the molar mass $(CO_2)$: $C: 12.01g + $ $O: 16.00g * 2= 32.00g$ = 44.01g/mol - Each $CO_2$ has 1 Carbon atom, therefore: $\frac{1moleC}{1moleCO_2}$ is the conversion factor. 2. Calculate the number of moles $(CO_2)$ $ 88g \times \frac{1 mole CO_2}{ 44.01g} \times \frac{1moleC}{1moleCO_2} = 2.0 moles C$