Answer
A total amount of $1.0 mCi$ should be given to that person.
Work Step by Step
1. Identify the objective.
- Calculate the amount of millicuries (mCi) of technetium-99m that should be given to a 50.0-kg person.
2. Find the conversion factors.
$\frac{20.µCi}{1kg}$ and $\frac{1kg}{20.µCi}$
$\frac{1mCi}{1000µCi}$ and $\frac{1000µCi}{1mCi}$
3. Calculate that amount:
$50.0kg \times \frac{20.µCi}{1kg} \times \frac{1mCi}{1000µCi} = 1.0 mCi$
Correct number of SFs: 2.
