Answer
a) CrO₃
b) S₂Cl₂
c) NiF₂
d) K₂HPO₄
e) AlN
f) NH₃
g) MnS₂
h) Na₂Cr₂O₇
i) (NH₄)₂SO₃
j) CI₄
Work Step by Step
a) Chromium (VI) has a 6+ charge and oxygen has a 2- charge. You would get Cr₂O₆ which would be reduced to CrO₃
b) di means two so that means you have two sulfur’s and 2 chlorides to get S₂Cl₂
c) Nickel (II) has a 2+ charge and fluorine has a 1- charge. Swap them and get NiF₂.
d) potassium has has 1+ charge and phosphate has a 3- charge. Since hydrogen can only give one electron that means there must be one hydrogen and two potassiums and one phosphate. That gives you K₂HPO₄
e) aluminum has a 3+ charge and nitrogen has a 3- charge. They cancel out so you get AlN.
f) ammonia is one of the formulas you just have to know which is NH₃
g) manganese (IV) has a 4+ charge in sulfur has a 2- charge. Switch charges to get Mn₂S₄. That then reduces down to MnS₂
h) sodium has a 1+ charge and dichromate has a 2- charge. Switch charges to get Na₂Cr₂O₇.
i) ammonium has a 1+ charge and sulfite has a 2- charge. Switch charges to get (NH₄)₂SO₃
j) there is no prefix in front of carbon which means there is one carbon, and tetra means four so that means there are four iodines. That gives you CI₄.
