Chapter 13 - Chemical Equilibrium - Exercises: 25

K = $4.0\times10^{6}$

Work Step by Step

According to the law of mass action, a general formula of the form jA + kB ⇌ lC + mD is represented by the following equilibrium expression: K = $\frac{[C]^{l}[D]^{m}}{[A]^{j}[B]^{k}}$ where A, B, C, and D represent the chemical species and j, k, l, and m are their coefficients in the balanced equation. Therefore, K = $\frac{[N_{2}][H_{2}O]^{2}}{[NO]^{2}[H_{2}]^{2}}$ K = $\frac{(5.3\times10^{-2})(2.9\times10^{-3})^{2}}{(8.1\times10^{-3})^{2}(4.1\times10^{-5})^{2}}$ K = $4.04\times10^{6}$ (carried one extra significant digits) K = $4.0\times10^{6}$

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