Chemistry 12th Edition

Published by McGraw-Hill Education
ISBN 10: 0078021510
ISBN 13: 978-0-07802-151-0

Chapter 13 - Chemical Kinetics - Questions & Problems: 13.28

Answer

Please see the work below.

Work Step by Step

We know that $\frac{1}{[A]}=\frac{1}{[A]_0}+Kt$ We plug in the known values to obtain: $\frac{1}{0.28}=\frac{1}{0.62}+0.54t$ This simplifies to $t=3.6s$
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