Answer
There are 20 positions possible for each position in the polypeptide. The mass of all the combinations possible for any protein is 32 x 110 x $20^{300}$ which is equal to $5.5\times10^{370}$.
Work Step by Step
There are 20 positions possible for each position in the polypeptide. The mass of all the combinations possible for any protein is 32 x 110 x $20^{300}$ which is equal to $5.5\times10^{370}$.
