Trigonometry 7th Edition

Published by Cengage Learning
ISBN 10: 1111826854
ISBN 13: 978-1-11182-685-7

Chapters 1-3 - Cumulative Test - Page 177: 24

Answer

$\frac{\sqrt {3}}{2}$

Work Step by Step

As $\sin(\pi-x)=\sin x$, we have $\sin \frac{2\pi}{3}=\sin(\pi-\frac{\pi}{3})=\sin\frac{\pi}{3}=\frac{\sqrt 3}{2}$
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