Answer
No triangle is possible.
Work Step by Step
\[
60^{\circ}=A , a=12 \text { inches, } 42 \text { inches }=b
\]
We know two sides and one angle; thus we will use the law of sines to find the reference angle.
\[
\begin{array}{l}
\frac{b}{\sin B}=\frac{a}{\sin A} \\
\frac{42}{\sin B^{\circ}}=\frac{12}{\sin 60} \\
\frac{\sin 60^{\circ}}{12} \cdot 42=\sin B \\
\frac{\sin 60^{\circ}}{12} \cdot 42=\sin B \\
3.03=\sin B
\end{array}
\]
Since sine values exist between -1 and 1, no such triangle is possible.
