Trigonometry 7th Edition

Published by Cengage Learning
ISBN 10: 1111826854
ISBN 13: 978-1-11182-685-7

Chapter 7 - Section 7.3 - The Ambiguous Case - 7.3 Problem Set - Page 391: 40

Answer

$36.9^{\circ},143.1^{\circ},216.9^{\circ}.323.1^{\circ}$

Work Step by Step

$7\sin^2{\theta} -9(1-2\sin^2{\theta}) = 0$ $7 \sin^2{\theta} + 18 \sin^2{\theta} = 9$ $ 25 \sin^2{\theta} = 9$ $\sin^2{\theta} = \dfrac{9}{25}$ $\sin{\theta}= \pm 0.6$ $\theta = 36.9^{\circ},143.1^{\circ},216.9^{\circ}.323.1^{\circ}$
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