Trigonometry 7th Edition

Published by Cengage Learning
ISBN 10: 1111826854
ISBN 13: 978-1-11182-685-7

Chapter 7 - Section 7.2 - The Law of Cosines - 7.2 Problem Set - Page 381: 64

Answer

b. $145.7^{\circ}$

Work Step by Step

Based on the cosine formula that $c^{2}$ = $a^{2}$ + $b^{2}$ - 2$ab$ $\cos$ $C$ We input the values of $a$ = 13.8 $b$ = 22.3, and $c$ = $9.5$ and rearrange the equation to get $\cos$ $C^{\circ}$ = $\frac{a^{2} + b^{2} - c^{2}}{2{a}{b}}$ , but we are finding $B$, so $\cos$ $B^{\circ}$ = $\frac{a^{2} + c^{2} - b^{2}}{2{a}{c}}$. inputting the values: $\cos$ $B^{\circ}$ = $\frac{13.8^{2} + 9.5^{2} - 22.3^{2}}{2(13.8)(9.5)}$ $\cos$$B^{\circ}$ = -0.8260869565 Therefore $\arccos$(-0.8260869565 = $B^{\circ}$ = 145.6988472 Rounding up, this gives the answer of 145.7
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