Trigonometry 7th Edition

Published by Cengage Learning
ISBN 10: 1111826854
ISBN 13: 978-1-11182-685-7

Chapter 5 - Test - Page 315: 17

Answer

$\frac{1+\sqrt3}{2\sqrt2}$.

Work Step by Step

We know that $\sin(A/2)=\pm\sqrt{\frac{1-\cos A}{2}}$. Hence here $\sin 75=\pm\sqrt{\frac{1-\cos 150}{2}}=\pm\sqrt{\frac{1-(-\frac{\sqrt3}{2})}{2}}=\frac{1+\sqrt3}{2\sqrt2}$.
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