Answer
x
Work Step by Step
Let $\sin ^ {–1} \frac{1}{x} = \theta$
then, $\sin \theta = \frac{1}{x}$
To evaluate $\csc (\sin ^ {–1} \frac{1}{x}) = \csc \theta$
We know that, $\csc \theta = \frac{1}{\sin \theta}$
Using above relations we get
$\csc \theta = \frac{1}{\frac{1}{x}}$
$=> \csc \theta = x$
