Answer
$\dfrac{2\pi}{|B|}$
Work Step by Step
As we are given that $y=A \sin (Bx) +D$
Thus, amplitude $=|A|$
and
the period is : $\dfrac{2\pi}{|B|}$
So, for the function $y= \sin (Bx) $
The period is : $\dfrac{2\pi}{|B|}$
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