Trigonometry 7th Edition

Published by Cengage Learning
ISBN 10: 1111826854
ISBN 13: 978-1-11182-685-7

Chapter 2 - Test - Page 112: 19

Answer

$b = 41.5$ units $A = 30.3˚$ $B = 59.7˚$

Work Step by Step

1. Find the missing length $b$ $a^{2} + b^{2} = c^{2}$ $(24.3)^{2} + (b)^{2} = (48.1)^{2}$ $(b)^{2} = (48.1)^{2} - (24.3)^{2}$ $b = \sqrt (2313.61 - 590.49)$ $b = \sqrt (1723.12)$ $b = 41.5104806$ units $b = 41.5$ units 2. Find the missing angles $\angle A$ and $\angle B$ $\frac{sin(A)}{24.3} = \frac{sin(90)}{48.1}$ $sin(A) = \frac{24.3sin(90)}{(48.1)}$ $sin(A) = \frac{24.3}{48.1}$ $sin(A) = 0.5051975...$ $A = 30.3˚$ Area of a triangle $= 180˚$ $A + B + C = 180$ $30.3 + 90 + B = 180$ $120.3 + B = 180$ $B = 59.7˚$
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