Answer
$(\frac{\sqrt5}{3}, -\frac{2}{3})$) is found on the graph of the unit circle.
Work Step by Step
A unit circle is a circle with a radius of one, with a center on the origin (0,0).
Therefore the point $(\frac{\sqrt5}{3}, -\frac{2}{3})$), is found on the unit circle.
To check for this, substitute the x and y values of the point into the area of a circle as well as the radius.
$x^2+y^2=r$
$(\frac{\sqrt5}{3})^2+(-\frac{2}{3})^2=1$ Substitute.
$\frac{5}{9}+\frac{4}{9}=1$
$\frac{9}{9}=1$
$1=1$
