Trigonometry (10th Edition)

Published by Pearson
ISBN 10: 0321671775
ISBN 13: 978-0-32167-177-6

Chapter 6 - Inverse Circular Functions and Trigonometric Equations - Section 6.1 Inverse Circular Functions - 6.1 Exercises - Page 260: 90

Answer

$csc~(csc^{-1}~\sqrt{2}) = \sqrt{2}$

Work Step by Step

Let $~~\theta = csc^{-1}~\sqrt{2}$ Then: $~~csc~\theta = \sqrt{2}$ Therefore, $~~csc~(csc^{-1}~\sqrt{2}) = \sqrt{2}$
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