Answer
23.58% of students taking the MCAT had a score of over 30.
Work Step by Step
$ (30-25.3)/6.5 = z$
$4.7/6.5 = z$
$z = .723$
.7642 is the normal value for $z=.72$
$1 - .7642 = .2358$
The Basic Practice of Statistics 7th Edition
by Moore, David S.; Notz, William I.; Fligner, Michael A.
Published by
W. H. Freeman
ISBN 10:
146414253X
ISBN 13:
978-1-46414-253-6
Chapter 3 - The Normal Distributions - Apply Your Knowledge - Page 91: 3.12a
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