Answer
$(0.00576496,0.01225904)$
Work Step by Step
The degree of freedom is the sample size minus $2$: $df=n-2=4-2=2$.
The critical value is given in the row $df=2$ and in the column with $c=0.9$ of the table. Thus $t=2.92$.
The confidence interval is then: $b\pm tSE_b=0.009012\pm2.92\cdot0.001112$, thus the confidence interval is $(0.00576496,0.01225904)$
