Answer
$(0.5981,0.7894)$
Work Step by Step
$\hat{p}=\frac{x}{n}=\frac{65}{94}\approx0.6915$
The z-value belonging to the $95\%$ confidence interval according to the table is $z=1.96$, thus the confidence interval is: $\hat{p}\pm z\sqrt{\frac{p(1-p)}{n}}$, which here is: $0.6915\pm 1.96\sqrt{\frac{0.6915\cdot(1-0.6915)}{94}}$, thus the confidence interval is $(0.5981,0.7894)$