Answer
$0.1695$ to $0.2219$
Work Step by Step
$\hat{p}=\frac{171+2}{880+4}\approx0.1957$
The z-value belonging to the $95\%$ confidence interval according to the table is $z=1.96$, thus the confidence interval is: $\hat{p}\pm z\sqrt{\frac{p(1-p)}{n}}$, which here is: $0.1957\pm 1.96\sqrt{\frac{0.1957\cdot(1-0.1957)}{884}}=0.1957\pm0.0262$
Thus the interval is from $0.1695$ to $0.2219$
