Answer
$0.8106$
Work Step by Step
$z=\frac{\overline{x}-\mu}{\sigma/\sqrt n}=\frac{0.5202-0.8}{1/\sqrt{10}}\approx-0.88$
Thus, using the table, the probability of rejecting the null hypothesis: $P(Z\gt-0.88)=P(Z\lt0.88)=0.8106$
The Basic Practice of Statistics 7th Edition
by Moore, David S.; Notz, William I.; Fligner, Michael A.
Published by
W. H. Freeman
ISBN 10:
146414253X
ISBN 13:
978-1-46414-253-6
Chapter 18 - Inference in Practice - Chapter 18 Exercises - Page 437: 18.48c
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