Answer
$1570.7963,18.3602$
Work Step by Step
The mean of a binomial distribution: $\mu=np=2000\cdot\pi/4=1570.7963$
The standard deviation of a binomial distribution: $\sigma=\sqrt{npq}=\sqrt{np(1-p)}=\sqrt{2000\cdot\pi/4\cdot(1-\pi/4)}=18.3602$
