The Basic Practice of Statistics 7th Edition

Published by W. H. Freeman
ISBN 10: 146414253X
ISBN 13: 978-1-46414-253-6

Chapter 13 - General Rules of Probability - Chapter 13 Exercises - Page 324: 13.52b

Answer

The chances that a randomly selected person is Asian given that he/she is glucose tolerant is: P(A|L) = $\frac{P(A and L)}{P(L)}$ = $\frac{P(L|A) . P(A)}{P(L)}$ = (0.9 0.04) / (0.252) = 0.14 Hence, 14% of the lactose tolerant people are Asian.

Work Step by Step

The chances that a randomly selected person is Asian given that he/she is glucose tolerant is: P(A|L) = $\frac{P(A and L)}{P(L)}$ = $\frac{P(L|A) . P(A)}{P(L)}$ = (0.9 0.04) / (0.252) = 0.14 Hence, 14% of the lactose tolerant people are Asian.
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