Essentials of Statistics (5th Edition)

Published by Pearson
ISBN 10: 0-32192-459-2
ISBN 13: 978-0-32192-459-9

Chapter 6 - Normal Probability Distributions - Review - Review Exercises - Page 311: 10

Answer

a) ..70 b) .11

Work Step by Step

a. We find: $\mu=np=(64)(.8)=51.2$ $ \sigma=\sqrt{npq}=\sqrt{(64)(.8)(.2)}=3.2$ Thus, we find z: $z=\frac{49.5-51.2}{3.2}=-.53$ Thus, using the table of z-scores, we find that this corresponds to a probability of $1-.30=.70$ b. We must find the second z-score: $z=\frac{50.5-51.2}{3.2}=-.22$ Thus, using the table of z-scores, we find that this corresponds to a probability of $.41-.3=.11$
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